Tomb Raider: Definitive Edition is now available on Nintendo Switch 2 & Nintendo Switch.
Experience the cinematic action-adventure that forced Lara Croft to grow from an inexperienced young woman into a hardened survivor. Lara must endure high-octane combat, customize her weapons and gear, and overcome grueling environments to survive her first adventure and uncover the island’s deadly secret.
This is gonna be on Switch 1 as well? I would advise not buying it there, for the same reason I don’t recommend The Outer Worlds. Well, The Outer Worlds looks and runs like trash on Switch, but it looked great on PC and Xbox.
Switch 2 is probably much more capable.
Fans of The Outer Worlds (and Bloodstained) on Switch will say “well it’s the only way I can play it on mobile” and I guess that’s a fair point, but it’s still not a great experience.
I haven’t seen how it runs on Switch 1, but it was originally a PS3 game, so Switch should be able to run it well. Depends on the port though.Edit: SwitchUp review is out, yeah Switch 1 might not be the best choice, specially if you have another platform where you can play it on:
Review link: https://www.youtube.com/watch?v=xutVcQ5Nxkg
Uh, the steam deck is mobile enough and you can squeeze anywhere from 2h30 to 4h+ of gametime for both games with better settings than either of the switch consoles.
It’s not true that the switch version is the only way to play it on mobile. It’s not even the best way to do so 😏
it’s the only way I can play it on mobile
Runs perfectly on the steam deck
I guess you can play these on Steam Deck (and similar), but they are far less mobile than Switch.
Very reasonable price (for Nintendo anyway), 30fps for Switch 1 and 60fps for Switch 2. Slightly increased texture resolution for Switch 2 (vs 1).
This was a great game, but it’s pretty cheap on pc. I wonder what this price will be.
$19.99, but currently on launch sale for $17.99
That’s not too bad to be honest. I was expecting them to go much higher.
Yeah, same here. I was expecting the Switch tax, but this seems reasonable.
Polygonal Peaks
